Abstract
<p> Let H∈Cn×n have real eigenvalues λ1(H)≥⋯≥λn(H). It is known that if G and H are two nonnegative matrices, then ∑kt=1λt(GH)≥∑kt=1λt(G)λn−t+1(H). The authors prove that in this case if 1≤i1 ∑t=1kλit(GH)≥∑t=1kλit(G)λn−t+1(H) and ∑t=1kλt(GH)≥∑t=1kλit(G)λn−it+1(H).</p>
| Original language | American English |
|---|---|
| Journal | Journal of Beijing Normal University |
| Volume | 1987 |
| State | Published - Jan 1 1987 |
Keywords
- Eigenvalue
- Matrix
- Singular value
Disciplines
- Mathematics
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